Solve the following equation using the method | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the equation: $x - \frac{20}{x} = 1$Multiply the entire equation by $x$ to eliminate the fraction: $x^2 - 20 = x$Rearrange the equation into

Vedclass · Accepted Answer

$5, -4$

Vedclass · Answer

(A) Given the equation: $x - \frac{20}{x} = 1$Multiply the entire equation by $x$ to eliminate the fraction: $x^2 - 20 = x$Rearrange the equation into the standard quadratic form $ax^2 + bx + c = 0$: $x^2 - x - 20 = 0$To factorize,find two numbers that multiply to $-20$ and add to $-1$: These numbers are $-5$ and $4$.Rewrite the middle term: $x^2 - 5x + 4x - 20 = 0$Group the terms: $x(x - 5) + 4(x - 5) = 0$Factor out the common binomial: $(x - 5)(x + 4) = 0$Set each factor to zero: $x - 5 = 0$ or $x + 4 = 0$Thus,the solutions are $x = 5$ or $x = -4$.

Solve the following equation using the method of factorization: $x - \frac{20}{x} = 1$

Similar Questions

The speed of a motor-boat in still water is $x \, km/hr$ and the speed of the current of the river is $5 \, km/hr$. Given $x$ > 5, what is the time taken to cover a distance of $y \, km$ upstream?

The roots of the quadratic equation $3x^2 - 4x + 1 = 0$ are:

The solution set of a quadratic equation $x^{2}+5x-14=0$ is $\ldots \ldots \ldots \ldots .$

Verify whether the given value of $x$ is a solution of the quadratic equation or not: $2x^2 - 5x + 3 = 0$; $x = \frac{1}{2}$.

The roots of the quadratic equation $x + \frac{2}{x} = 3$ are $\dots$ $(x \neq 0)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module